Pipes A And B Can Fill A Tank. Pipe a is opened first at time t = o and pipe c is opened at the instant when the tank is exactly half filled with water. Pipe b alone can fill a tank in = 2 hrs.
Since pipe b is faster, the tank will be emptied. Pipe a and b can fill a tank in 12 and 15 hours respectively. Pipe b can fill a tank in 6 hours.
Find The Time Required To Empty The Tank?
In this type of questions we first get the filling in 1 minute for both pipes then we will add them to get the result, aspart filled by a in 1 min = 1/20part filled by b in 1 min = 1/30part filled by (a+b) in 1 min = 1/20 + 1/30= 1/12so both pipes can fill the tank in 12 mins. Part filled by b in 1 h = 1 6. Both the pipes are opened together but 4 minutes after the start the pipe a is turned off.
In This Type Of Questions We First Get The Filling In 1 Minute For Both Pipes Then We Will Add Them To Get The Result, As Part Filled By A In 1 Min = 1/20 Part Filled By B In 1 Min = 1/30 Part Filled By (A+B) In 1 Min = 1/20 + 1/30 =.
Two pipes a and b can fill a tank in 15 hours and 20 hours, respectively, while a third pipe c can empty the full tank in 25 hours. Because of a leak, it took 21 3 hours to fill the tank. Since pipe a is open for 18 minute water filled by it = 18 × 4 = 72 units.
Since One Hour Work Of C Is Greater Than B So Tank Will Be Emptied When Both Work Together.
An outlet pipe c, can empty it in 6 hours. Two pipes a and b can separately fill a tank in 2 minutes and 15 minutes respectively. Pipes a and b can completely fill a water tank in 4 hours and 5 hours respectively.
The Total Time (In Hours) Taken To Fill The Tank.
All the three pipes are opened in the beginning. Part emptied in by a and b 1 min = 1/15. C is an outlet pipe attached to the tank.
Three Pipes A, B And C Can Fill A Tank From Empty To Full In 30 Minutes, 20 Minutes And 10 Minutes Respectively.
Time taken to empty 2/5 of the tank = (⅖)/(1/15) = 6 min. Therefore, efficiency of a and b together = 100 %. Hence option b is the answer.